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標題:
Let f(x) = x^2 + 10x +24
發問:
Let f(x) = x^2 + 10x +24 (a) Factoeize f(x) (b) Hence or otherwise,factorize f( p^2 - 5p )
最佳解答:
(a) f(x) = x^2 + 10x +24 =(X+4)(X+6) (b) f( p^2 - 5p ) =( p^2 - 5p )^2+10( p^2 - 5p )+24 =( p^2 - 5p +4)( p^2 - 5p +6) =(p-1)(p-4)(p-2)(p-3) =(p-1)(p-2)(p-3)(p-4)
其他解答:
(a) (x+4)(x+6) (b) (p-1)(p-4)(p-2)(p-3)|||||(a) (x+4)(x+6) (b) f(p^2-5p) = (p^2-5p+4)(p^2-5p+6) = (p-1)(p-4)(p-2)(p-3)|||||a)f(x)=x^2+10x+24 =(x+4)(x+6),x=-6or-4 b)f(p^2-5p)=(p^2-5p)^2+10(p^2-5p)+24 =(p^2-5p+4)(p^2-5p+6) =(p-4)(p-1)(p-2)(p-3)
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